Okay, haven't looked at chemistry since about 1990. I can usually remember how to do stuff after I look around online for reminders, but this one, I just can't quite remember.
The problem:
Solutions of aluminum sulfate and calcium hydroxide are mixed. What is the mass of precipitate formed when 250ml of 3.4M aluminum sulfate is mixed with 100ml of 7.4M calcium hydroxide.
So I balance the equation, and I'm pretty sure it ends up being
Al2(SO4)3 + 3Ca(OH)2 ---> 3Ca(SO4) + 2Al(OH)3
with 2Al(OH)3 being the precipitate.
The problem is that I can't remember where to go from here, so I'll throw down what I've done and hopefully someone can continue to point me in the right direction.
.250L * { 3.4mol Al2(SO4)3 / L } * { 342g Al2(SO4)3 / mol Al2(SO4)3 } * { 2 mol Al(OH)3 / 1 mol Al2(SO4)3 } = 581.4g Al(OH)3
so that's what I have. I don't know if it's correct. I don't know if I even performed the operation properly, although the units and such seem to cross out and leave me with the appropriate thing at the end
So even assuming all of the above was performed correctly and is relevant, how do I incorporate the 100ml of 7.4M Calcium hydroxide? Do I need to do so? How can I tell if the amount of my precipitate will be limited by the amount of the Al "supplier" or the hydroxide "supplier"?