Hello everyone,
With the following problem, my answer was slightly different from the provided one. Could anyone please see if what the problem may be?
Thank you.
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1. The following reaction takes place in a sealed 40.0 L container at 120°C.
4NH3 + 5O2 --> 4NO + 6H2O
When 34.0 g of NH3 react with 96.0 g O2, what will be the total pressure in the flask at the end of the reaction?
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34.0 g 96.0 g
= 2.00 mols = 3.00 mols
Ammonia would be the limiting reagent.
Therefore:
= 2.00 mols x (10/4)
= 5.00 mols
After using P = (nRT)/V, I get 408 kPa. However, the answer is 449 kPa.