December 23, 2024, 02:36:12 AM
Forum Rules: Read This Before Posting


Topic: Normality help please  (Read 3150 times)

0 Members and 2 Guests are viewing this topic.

Offline ss4adam

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Normality help please
« on: May 08, 2008, 12:53:53 PM »
i basically have a final tonight and dont understand how equvelents work. i missed a true/false problem on a test that went like this


normality is always greater than or equal to molarity

since normality is equiv/liter it seems like the answer is TRUE because equivelents is less than or equal to normality ???


Please help
« Last Edit: May 08, 2008, 01:34:45 PM by ss4adam »

Offline M:B

  • Regular Member
  • ***
  • Posts: 14
  • Mole Snacks: +0/-0
  • Gender: Male
Re: Normality help please
« Reply #1 on: May 10, 2008, 05:10:52 PM »
1 eq/L neutralises 1 eq/L (eq = equivalent)
A 3N solution of Mg2+ (3eq/L) will neutralise a 3N solution of OH-.
The ratio of charge is 2:1 thus 2 OH- ions neutralised by 1 Mg2+ ion.
So the molar concentraions would be [OH-] = 3M and [Mg2+]  = 1.5M per unit volume.
Here the molarity of Mg2+ is 0.5(Normality).
Using this principle, the normality will always be greater than or equal to the molarity value since half a charge does not exist.

Another perspective: In a xM solution of an ion with charge = y, normality = xy.

Eg. 0.15M of Al(OH)3 = 0.15mol/L. Since charge of Al ion = 3+.Normality = 3(0.15) = 0.45 eq/L = 0.45N

Sponsored Links