November 24, 2024, 02:35:42 AM
Forum Rules: Read This Before Posting


Topic: pH of several solutions  (Read 10167 times)

0 Members and 1 Guest are viewing this topic.

Offline Wheeler004

  • New Member
  • **
  • Posts: 4
  • Mole Snacks: +0/-0
pH of several solutions
« on: June 04, 2008, 05:40:24 PM »
I need some help getting the pH of some solutions:

-pH of a solution of 10.0 mL of 0.1 M NH4Cl plus 10.0 mL of 0.1 M NaOH
-pH of a solution of 10.0 mL of 0.1 M NH4Cl plus 15.0 mL of 0.1 M NaOH
-pH of a solution of 10.0 mL of 0.1 M NaC2H3O2 plus 10.0 mL of 0.1 M NaOH
-pH of a solution of 10.0 mL of 0.1 M NaC2H3O2 plus 15.0 mL of 0.1 M NaOH
-pH of 50 mL of solution that is 0.25 M in both H2PO41- and HPO42-.

For the life of me I can't figure out how to do these problems, so if someone could show me how I would appreciate it.  Thanks.
« Last Edit: June 04, 2008, 06:05:00 PM by Wheeler004 »

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27858
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: pH of several solutions
« Reply #1 on: June 04, 2008, 06:11:09 PM »
Write reaction equation whenever it looks like the reaction is possible. In most cases pH will be controlled by the excess of one reagent.

As for the last one - do you know Henderson-Hasselbalch equation?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Wheeler004

  • New Member
  • **
  • Posts: 4
  • Mole Snacks: +0/-0
Re: pH of several solutions
« Reply #2 on: June 04, 2008, 06:25:56 PM »
OK, thanks for the website.  After doing the equation for the last solution, I got 5.05.  It looks right to me, but it's being counted as wrong when I submit it.

Offline AWK

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7976
  • Mole Snacks: +555/-93
  • Gender: Male
Re: pH of several solutions
« Reply #3 on: June 05, 2008, 12:58:57 AM »
For the last solution pH=pK2of H3PO4= 7.2
AWK

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27858
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: pH of several solutions
« Reply #4 on: June 05, 2008, 02:49:20 AM »
After doing the equation for the last solution, I got 5.05.

Show how you get to 5.05.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Wheeler004

  • New Member
  • **
  • Posts: 4
  • Mole Snacks: +0/-0
Re: pH of several solutions
« Reply #5 on: June 05, 2008, 04:52:35 PM »
Okay, I got the last one using the H-H formula.  The first time I was just using pKa.  Any help on the first four?  How do I calculate the H3O+ concentration for those?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27858
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: pH of several solutions
« Reply #6 on: June 05, 2008, 06:13:17 PM »
I hate to repeat myself.

Write reaction equation whenever it looks like the reaction is possible. In most cases pH will be controlled by the excess of one reagent.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Wheeler004

  • New Member
  • **
  • Posts: 4
  • Mole Snacks: +0/-0
Re: pH of several solutions
« Reply #7 on: June 05, 2008, 08:21:14 PM »
Yeah, I've tried that.  For the first one, there are 10ml of .1M acid and 10mL of .1M base.  Doesn't that mean that there is no excess of either?  I tried a pH of 7, but that's not the right answer.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27858
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: pH of several solutions
« Reply #8 on: June 06, 2008, 03:00:11 AM »
Yeah, I've tried that.  For the first one, there are 10ml of .1M acid and 10mL of .1M base.  Doesn't that mean that there is no excess of either?  I tried a pH of 7, but that's not the right answer.

But you are close - just think it over. You started with witch a weak acid and you neutralized it with a stoichiometric amount of the strong base. What ions/molecules do you have in solution after that? Is there any that can change pH of the solution?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links