[kerilynn]

A package of compounds used to achieve rehydration in sick patients contain 20.0 g of glucose, C6H12O6. When this material is diluted to 1.00 L, what is the molarity of glucose?


20.0 g C6H12O6 X 1 mol / 180.16 g C6H12O6 = 0.111 mol C6H12O6

0.111 mol C6H12O6 / 1.00 L = 0.111 mol / L = 0.111 M C6H12O6


is this right or can u tell me what i did wrong and lead me to the right way !!!

[azmanam]

looks good

[Borek]

OK

[AWK]

OK

For mass 20 g the result should be rounded to 0.11 M but for 20.0 the result is OK