0.130g of a sample of impure iron was dissolved in excess dilute sulfuric acid to form iron (II) sulfate. This was then titrated with a 0.0137 mol dm-3 solution of dichromate ions (Cr2O72- and was found to be just sufficient to reduce 27.3cm3 of the solution to chromium (III) ions (Cr3+).
The balanced ionic equation for the titration reaction is:
6Fe2+(aq) + Cr2O72-(aq) + 14H+(aq) ---> 6Fe3+ + 2Cr3+(aq) + 7 H2O(l).
However I don't understand how it was formed from the information given. Where did the H+ ions come from, and why the hydrogen ions are needed. Also if possible could anyone tell me which were the spectator ions and so on. I'm getting really confused.