[rcrystal]

Hello.
I have this equation:
K2S3O6 + KClO + KOH ---> K2SO4 + KCl + H20

Here is what I have and what I am stuck on:

I have figured the half reaction for Cl,
Cl^1+ ---> 2e- + Cl^1-
However, when I am trying to find the half reaction for S. I have the following problem:

An S ion has a charge of 10/3, what can I do to simplify the half reaction.

Thanks in advance

[Astrokel]

hello rcrystal, you should start with the sulpur containing ion as below. It is not balanced though...

S₃O₆^2-  ----> SO₄^2-

hope this helps some

[AWK]

Cl^1+ ---> 2e- + Cl^1-

should be:
Cl^1+  2e- --->  Cl^1-

An S ion has a charge of 10/3, what can I do to simplify the half reaction.

You should balance electrons for molecule, not for one atom
(3 x 10/3 = 3)
This is an equivalent to hint of Astrokel

[rcrystal]

Thank you. =) I have figured it out =D