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Topic: Simple Stoichiometry (Reactions in Solutions)  (Read 4054 times)

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Offline calvert11

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Simple Stoichiometry (Reactions in Solutions)
« on: September 25, 2008, 04:13:44 PM »
Question
What mass of solid forms upon mixing 50.0 mL of 3.30 M sodium hydroxide with 35.0 mL of 1.00 M magnesium chloride?

Attempt
2NaOH + MgCl2 -> 2NaCl + Mg(OH)2 ***Mg(OH)2 is the solid

I thought that I should find the limiting reactant and convert that into moles of the solid and then into grams. But the answer is wrong. Any ideas on how to solve this problem?

Offline Borek

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Re: Simple Stoichiometry (Reactions in Solutions)
« Reply #1 on: September 25, 2008, 04:52:34 PM »
How much solid did you get?

Perhaps you should take solubility (Kso) into account.
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Offline calvert11

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Re: Simple Stoichiometry (Reactions in Solutions)
« Reply #2 on: September 25, 2008, 06:20:32 PM »
How much solid did you get?

Perhaps you should take solubility (Kso) into account.
It was far larger than it should have been. (23 g is correct, I got 178).

But are you saying my approach to the problem is correct?

However, what's "Kso"? If you're saying I should take into account the degree of solubility of the compounds, I think that's a bit beyond what I'm studying now. Just knowing whether the compound is soluble should be enough to solve the problem. I'm taking Chemistry 1, non honors.

Offline Borek

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Re: Simple Stoichiometry (Reactions in Solutions)
« Reply #3 on: September 25, 2008, 06:27:09 PM »
(23 g is correct, I got 178).

Both are wrong if it makes you feel better.

Quote
But are you saying my approach to the problem is correct?

Yes.

How many moles of NaOH?

How many moles of MgCl2?

Which one is limiting?

How many moles of the product?

What is mass of the product?

Quote
However, what's "Kso"? If you're saying I should take into account the degree of solubility of the compounds, I think that's a bit beyond what I'm studying now. Just knowing whether the compound is soluble should be enough to solve the problem. I'm taking Chemistry 1, non honors.

If you don't know what Kso is (it is called solubility product by the way) you are most likely right that you should not bother.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline calvert11

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Re: Simple Stoichiometry (Reactions in Solutions)
« Reply #4 on: September 25, 2008, 07:02:57 PM »
Quote
But are you saying my approach to the problem is correct?

Yes.

How many moles of NaOH?

How many moles of MgCl2?

Which one is limiting?

How many moles of the product?

What is mass of the product?
Thanks for the help. I've got the answer. :)

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