[JoeJoe]

Hi guys, me again I just had a few questions.

First, I'll start with the concentration question.
Q1: A water source has a certain concentration of CuSO4. How could the results in step 8 be used to help ascertain an approximate concentration of CUSO4 in the water?

Heres what I think.
A1: The strength of the concentration of CuSO4 is apparent from the blue color intensity. The more dilute it is, the lighter it will be. The darker it is, the more concentrated the solution is.

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Q2: Explain the importance of dissolving the solute in a smaller volume of solvent
A2: If you try to dissolve a solute in a larger volume of solvent, the solute would become the solvent (and the solvent the solute).

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Q3:Calculate the mass of sucrose (C12H22O11) in grams required to prepare 500ml of 2M solution.
A3:
C12 = 12.0107x12=144.1284g/mol
H22 = 1.00794x22=22.17468g/mol
O11 = 15.9994x11 = 175.9934g/mol
                             ___________
                             342.29646g/mol
                             342.3g/mol

Where do I go from here?


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Q4: A 60ml volume of 3 M CuSO4 is mixed with 60ml of 2M CuSO4. Calculate the concentration of the Cu2+ ions in the final solution.

A4: I have no clue how to begin to answer this, any tips?

[Borek]

1. What is step 8? How can we be sure it is not related to - say - step 11?

2. Sorry, but it so off it is just funny.

3. How much copper? What final volume? What is concentration definition?

[JoeJoe]

1. What is step 8? How can we be sure it is not related to - say - step 11?

2. Sorry, but it so off it is just funny.

3. How much copper? What final volume? What is concentration definition?

2. Can you explain for me? I do not understand the question.

3. 120ml is the volume, how do I figure out the copper? Just add the 2 (3M+2M/2=2.5M)?

The molar concentration is number of moles per liter of solution.
So would this be:
5M/.1200ml = 41.666
or
2.5M/.1200ml = 20.833

I'm sorry I kinda lost and taking stabs

[Borek]

Looks to me like these questions are taken from some lab manual or something, they don't make sense taken out from context.

Write formula for molar concentration. Solve it for n.

[JoeJoe]

Looks to me like these questions are taken from some lab manual or something, they don't make sense taken out from context.

Write formula for molar concentration. Solve it for n.

Yes, they are from a lab manual. Trying to finish so I can have the weekend homework free ;\ Thanks for taking the time to respond to me.

Question:Calculate the volume required from 12M HCl to prepare 130ml of 0.3000M HCl
Answer:
12M x V1 = 0.3000M x .1300L
V1 = .3000Mx.1300L/12M
V1 = .00325L
3.25ml

Seems like such a small amount, I feel like I calculated it wrongly?

[Borek]

3.25 it is.