December 22, 2024, 11:48:03 PM
Forum Rules: Read This Before Posting


Topic: Equilibrium constant as a function of temperature?  (Read 4004 times)

0 Members and 1 Guest are viewing this topic.

Offline eagerinsight

  • New Member
  • **
  • Posts: 6
  • Mole Snacks: +0/-0
Equilibrium constant as a function of temperature?
« on: September 25, 2008, 06:39:03 PM »
If I was given an equilibrium constant as a function of temperature:

lnK = (58690K/T) - 12.04         In a temp range of (400 to 700 K)

I need to solve for entropy enthalpy and gibbs at 600 K, but where do I start, do I have to integrate (which I have know idea how to do), I figure I need to use the Van't Hoff equation but I don't know how to plug this value into dlnK/dT=dH/RT^2. Any hints how to get started?

Offline eagerinsight

  • New Member
  • **
  • Posts: 6
  • Mole Snacks: +0/-0
Re: Equilibrium constant as a function of temperature?
« Reply #1 on: September 25, 2008, 09:21:53 PM »
I think that 58690K is a temperature in kelvin, what value would I use T in the equation for the equilibrium constant? 600K?

With a value of lnK can I just plug that into -ΔG=RTlnK using 600K as my temperature?

Offline Yggdrasil

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 3215
  • Mole Snacks: +485/-21
  • Gender: Male
  • Physical Biochemist
Re: Equilibrium constant as a function of temperature?
« Reply #2 on: September 28, 2008, 11:34:51 AM »
I haven't worked this out, so this may be a wrong hint, but recall that:

ΔG = ΔH - TΔS

What does this suggest about the temperature-dependent and temperature-independent parts of your expression for lnK?

Sponsored Links