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Topic: Ionic compound formula?  (Read 2516 times)

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Offline Soulshine

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Ionic compound formula?
« on: September 27, 2008, 02:40:49 PM »
I'm stuck with this question in my chemistry book, but the question shows the answer and a solution why.
I still don't understand how and why  :-\. Barium ion and iodide ion - the answer is BaI2; the book shows the solution and why, but I don't understand it still. I got my answer correct for lithium ion and bromide ion, which is just LiBr. Anyhow, how the heck is barium ion is +2 and iodide is -1, is it because Barium is on 2A? @_@ Another problem of mine is Aluminum ion and Sulfied ion. It says that Al charge is +3, when I look at the periodic table, Al is on 3A; sulfur is on 6A @_@...Sulfied is a monatomic atom, so S^2-?
I peaked to the answer which is Al2S3. Al 3 became a 2 because it transferred its electron to S, now S3.
Does it mean that Al lost 3 electrons and sulfide ion gained 2?

Offline Borek

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Re: Ionic compound formula?
« Reply #1 on: September 27, 2008, 03:05:43 PM »
Yes, Ba is 2+ because it of its position in periodic table. Same about Al being +3 and S being -2.

Sulfide, not sulfied.

Monoatomic atom.... nice one :)

Yes, Al lost three electrons to became Al3+, yes, S gained 2 electrons to become S2-. Molecule has to be electrically neutral, so it will be Al2S3 - 6 electrons lost by two Al went to three S.
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