Q#1)
A piece of nickel foil, 0.550 mm thick and 1.25 cm on each side, reacted with fluorine, F
2, to give a nickel fluoride. The density of nickel is 8.908 g/cm^3.
a) How many moles of nickel foil was used?
b) If you isolate 1.261 g of nickel fluoride, what is its formula?
c) what is the stock system name of this compound?
Is the following calculation correct for 1a?:
Ni
2+(s) + F
2(g) NiF
2M
Ni = 58.690 g/mole
P
Ni = 8.908 g/cm
3T
Ni = 0.055 cm
V = 0.086 cm
3n
Ni = (P
Ni)/(M
Ni) * Volume
(0.152 mol/cm
3) * (0.086 cm
3)
nNi = 0.013 molQ#2)
Uranium is used as a fuel, primarily in the form of uranium (VI) oxide, in nuclear power plants. The following calculations are based on uranium chemistry.
A small quantity of uranium metal, 0.169g, was heated in air to between 800-900*c to give 0.199g of dark green oxide, U
xO
y.
a) How many moles of uranium metal were used?
b) how many moles of U
xO
y were obtained?
Is this correct:
O
2 is L.R.
0.199 g UO
3 * (mol UO3)/(286.0273 g UO3) * (2 mol U)/(2 mol UO3) * (238.029 g U)/(1 mole U) = 0.166 g U
U
avl. - U
used = 0.003 g U(s) =
1.23E-5 mol U(s) (Q#2a)
thx in advance