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Offline StillLearning

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Need help with oxidation states
« on: September 30, 2008, 12:21:10 AM »
I've attached an image in a document of the problem i'm working on.  For the life of me I cannot figure out how to solve this.  I thought oxygen had an oxidation number of -2??  I'm so lost.  Would someone PLEASE help me with this.  Thanks in advance.  :)

Offline nj_bartel

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Re: Need help with oxidation states
« Reply #1 on: September 30, 2008, 12:48:17 AM »
The oxidation state of pure uncharged elements (e.g. Cl2, Li) = 0, always.

Offline StillLearning

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Re: Need help with oxidation states
« Reply #2 on: September 30, 2008, 08:05:37 PM »
The oxidation state of pure uncharged elements (e.g. Cl2, Li) = 0, always.

Would you mind helping me with the the problem attached in my original post?  Even with your above advice, i'm still not able to correctly solve the problem.  I'm stuck.

Offline nj_bartel

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Re: Need help with oxidation states
« Reply #3 on: September 30, 2008, 09:04:14 PM »
What're the oxidation states of H2, N2, and O2?  Hint - do they consist of just one element?  Hint2 - what is the net charge on the compound?

Offline StillLearning

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Re: Need help with oxidation states
« Reply #4 on: September 30, 2008, 09:17:41 PM »
What're the oxidation states of H2, N2, and O2?  Hint - do they consist of just one element?  Hint2 - what is the net charge on the compound?

Well, everything on the reactant side is a single element, so should it be 0?  If this is the case, then how do I determine the oxidation states of the elements on the product side? 

Offline nj_bartel

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Re: Need help with oxidation states
« Reply #5 on: September 30, 2008, 09:26:19 PM »
You're right. Use your rules for heterogenous compounds now for the products.  Oxygen when combined with nitrogen has an oxidation state of...? -2. But your overall compound has a net charge of 0 and a molecular formula of N2O.  So 2*(oxidation state of N) + -2 (the oxidation state we already have given by oxidation rules for oxygen being bonded to nitrogen) = 0 

solve for the oxidation state of N.

Offline StillLearning

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Re: Need help with oxidation states
« Reply #6 on: October 01, 2008, 12:10:06 AM »
You're right. Use your rules for heterogenous compounds now for the products.  Oxygen when combined with nitrogen has an oxidation state of...? -2. But your overall compound has a net charge of 0 and a molecular formula of N2O.  So 2*(oxidation state of N) + -2 (the oxidation state we already have given by oxidation rules for oxygen being bonded to nitrogen) = 0 

solve for the oxidation state of N.

Ok I think i'm starting to understand, but i've got a few more questions:

1.  So the oxidation state of N is +1 since there are 2 N atoms for every 1 O atom, right? 
2.  The coefficients always get ignored when looking at oxidation states, right?   
3.  Why is that in the compound 2NH3 the anion comes first?  I thought the cation came first, or is that only in ionic compounds? 

Offline nj_bartel

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Re: Need help with oxidation states
« Reply #7 on: October 01, 2008, 12:19:13 AM »
1) right
2) right
3) Not entirely sure on that, been a while since I've done this stuff.  If it isn't just ionic compounds, then ammonia (NH3) might just be an exception because it could've been a compound that was discovered before the nomenclature was put in place.

Offline StillLearning

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Re: Need help with oxidation states
« Reply #8 on: October 01, 2008, 12:30:59 PM »
1) right
2) right
3) Not entirely sure on that, been a while since I've done this stuff.  If it isn't just ionic compounds, then ammonia (NH3) might just be an exception because it could've been a compound that was discovered before the nomenclature was put in place.

Hmm.  Ok.  I wont worry about that right now then.  I really appreciate your help. 

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