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Topic: net ionic equations  (Read 16734 times)

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Offline coolcep1

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net ionic equations
« on: October 01, 2008, 06:52:41 PM »
i need help writing net ionic equations for my chem lab in cases where a precipitate was formed.
they are:
sodium bromide and lead(II) nitrate
sodium bromide and silver nitrate
sodium carbonate and barium nitrate
sodium carbonate and calcium nitrate
sodium carbonate and cobalt(II) nitrate
sodium carbonate and lead(II) nitrate
sodium carbonate and magnesium nitrate
sodium carbonate and nickel(II) nitrate
sodium carbonate and silver nitrate
sodium carbonate and strontium nitrate


there are a bunch more, but if i could get some help on these i think i can do the rest. thank you.

Offline Borek

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Re: net ionic equations
« Reply #1 on: October 01, 2008, 07:03:57 PM »
sodium bromide and silver nitrate

Ag+(aq) + Br-(aq) -> AgBr(s)
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Offline coolcep1

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Re: net ionic equations
« Reply #2 on: October 01, 2008, 07:10:14 PM »
thank you.
so, is it pretty much taking the bromide out of the sodium bromide and then the compound out of the second part like silver nitrate? if it is sodium sulfate, is it sulfur, or is it different from the bromide example?

Offline StillLearning

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Re: net ionic equations
« Reply #3 on: October 01, 2008, 07:20:55 PM »
thank you.
so, is it pretty much taking the bromide out of the sodium bromide and then the compound out of the second part like silver nitrate? if it is sodium sulfate, is it sulfur, or is it different from the bromide example?

I was working on this stuff a few days ago, and if i'm not mistaken, I think you're oversimplifying the process.  You can only remove the ions that dont participate in the reaction. 

Offline Dan

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Re: net ionic equations
« Reply #4 on: October 01, 2008, 07:32:20 PM »
Quote
so, is it pretty much taking the bromide out of the sodium bromide and then the compound out of the second part like silver nitrate?

The point is that, for the sodium bromide and silver nitrate case, that AgBr is insoluble, and so Ag+ and Br- participate in the reaction forming a new solid product. The sodium nitrate left over is soluble and so remains as an aqueous solution of Na+ and NO3- ions - so these ions have not participated in the reaction and are spectator ions - these are not included in the net ionic equation.

if it is sodium sulfate, is it sulfur, or is it different from the bromide example?

The precipitate in this case is not sulfur. all these reactions are double displacement reactions. Have a look at this wiki page, paying special attention to the "aqueous metathesis" section.

http://en.wikipedia.org/wiki/Double_displacement_reaction

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Offline coolcep1

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Re: net ionic equations
« Reply #5 on: October 01, 2008, 07:35:31 PM »
thank you, that helps.

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