hi would you mind helping me check my work, because i have no solutions.
ai) Fe
3+ + e
- ---> Fe
2+ E = +0.77V
Ni -----> Ni
2+ +2e
- E = +0.25V
2Fe
3+ + Ni ---> Ni
2+ + 2Fe
3+ E
cell = +1.02V
aii) Ni electrode grows thinner and increasing green solution of Ni
2+. The solution in Fe
3+/Fe
2+ becomes more yellowish-green.
aiii) Q = It = 2 (10 x 60 x 60) = 72000 C
n
e = Q/F = 72000/96500 = 0.746mol
mass of Nickle electrode = (0.746/2) x 58.7 = 43.8g
bi) [Ni2+] = (0.746/2) / 1 = 0.373 mol dm
-3E
Ni2+/Ni = 0.25 - 0.0128 ln (1/0.373) = +0.237V
bii)
What does it mean "cell stopped working"?
i think it means the rate of forward reaction equal to the backward?