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Topic: Ka of this acid  (Read 3671 times)

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Offline a7m3l5a

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Ka of this acid
« on: October 06, 2008, 07:41:06 PM »
26.20 ml of 0.102M Naoh is needed to neutralize 25.00 ml of an unknown acid HA. The pH at the equivalence point was measured to be 8.77. What is the Ka of this acid?
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Offline AWK

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Re: Ka of this acid
« Reply #1 on: October 07, 2008, 01:05:53 AM »
Calculate stoichiometry of neutralization and use Henderson-Haselbach equation.
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Offline Borek

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Re: Ka of this acid
« Reply #2 on: October 07, 2008, 02:53:12 AM »
Quote from: AWK on October 07, 2008, 01:05:53 AM
Calculate stoichiometry of neutralization and use Henderson-Haselbach equation.

You don't use Henderson-Hasselbalch equation to calculate pH at the equivalence point.

Idential question was asked here:

http://www.chemicalforums.com/index.php?topic=28764
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