[TheToby]

While studying for a test, I came across the following question.  I realize that heat will flow from the hot copper block into the cold copper block and this will represent a change in heat.  I know that the formula will be q=CΔT with C=0.385 J K^-1g^-1 .  After this point I get lost in the method.  The question is

Calculate ΔHtotal and ΔStotal when two copper blocks each of mass 10.0 kg, one at 100.0^oC, and the other at 0.0^oC, are placed in contact in an isolated container.  The specific heat capacity of copper is 0.385 J K^-1g^-1 and may be assumed constant over the temperature range involved.

Please help me understand this.  Thanks!

[Hello12]

I thought the equation to use would be q=mc change T. If the you assumed the intial temparature of the blocks to room temparature i think the answer may be... q=10000*0.385*75. this will give you a q value. But if you want to work out the enthalpy change you will need to find the moles of the copper and divide this by the q value. I have no idea how to work out the ΔStotal sorry