Hi everyone!
I have a question about PPM. I have to solve the PPM of Fluoride in a standard of NaF. The amount of NaF is 1.0534g and the volume is 0.250L. I've found the molarity to be 0.1M.
So after that I did PPM = 0.1M * 41.99 (mw of NaF) * 1000 = 4213.59PPM.
This is the PPM of NaF in the solution, but how do I get the PPM of F?
Is it just the same, or do I have to substitute the mW of Fluorine into the PPM equation?
Thanks.