[bigdave1300]

Question:

A fuel may be deignated by the chemical formula C51 H105 S2 (OH)3

Write out the balance equation for complete combustion of this fuel.


Relevant equations

Cx Hy Oz Sn [(x) + (y/4)] o2

> xCo2 + (y/2) H2o


The problem is that I dont know how to simplify the (C51 H105 S2 (OH)3) to put it into the equation?

[Astrokel]

The compound is C₅₁H₁₀₅S₂(OH)₃?
.

[AWK]

C₅₁H₁₀₅S₂(OH)₃ = C₅₁H₁₀₈O₃S₂
Why simplify? Just do combustion reaction.

Each carbon atom needs 1O₂
Each sulfur atom needs 1O₂
Each oxygen atom takes two hydrogen atoms
Each 4 hydrogen atoms need 1O₂
51C + 51O₂ = 51CO₂
2S + 2O₂ = 2SO₂
3O + 6H = 3H₂O
The rest 102 hydrogen atoms react with O₂
102H + 102/4O₂ = 25.5H₂O

all should be multiply by 2

2C₅₁H₁₀₈O₃S₂ + ... O₂ = ... CO₂ + ... H₂O + ... SO₂