I went to work on it again and this is what I got.
I take my 0.1003 M NaOH and multiply it by 20.77 mL (which I will convert to L)
(0.1003 M NaOH)(.02077 L)= .002083
Then I take the .125 g sample of unknown acid and divide that by .002083
.125/.002083 = 60.0 g/mol of uknown acid!!!!
I did it!!! After pulling out all my hair!!!