I've been having some troubles solving this spectra. It's actually the first one in the exercises sheet, and doesn't come with an answer. I was hoping to get some feedback on how I'm attempting to solve it, and perhaps someone could give me some ideas on what I'm missing...
1) First thing I do is to check for any isotopic patterns from Cl and Br, none of them are there, so I discarded them.
2) I assume that m/z 101 is the M+ ion. The neutral loss from 101 to 86 is a loss of 15 which counts as a logical neutral loss m/z 15.
3) Ion series 15, 29, 43, 57 seems to be an alkane chain. From m/z 86 Int 11 and m/z 87 Int 0.4 I calculate that the numbers of carbons should be ~3 or 4.
((0.4/11)*100%)/1.1=3.3
4) If there's 4 Carbons forming an alkane series then that should cover 57 out of the 101 Da. 44 Da remains. It's probably here where I'm a bit lost and don't know what to do.
4.1) If I add two oxygen, then I will receive a remainder of 12 Da, which would be one carbon, but no hydrogen. Also, this can't be possible since counting the r+db (ring + double bonds) you receive a half integer, which would mean that 101 wasn't the M+.
4.2) Maybe an even numbers of nitrogen are present? 2 is the only amount that would fit. Remaining is 16 Da which would be an oxygen. This would result in a formula of C5N2OH9, r+db=1
Working with this formula I have a hard time finding which fragment results into 59. So I'm guessing that this is wrong as well...
There has to be a more efficient way to solve spectra? Any advice?