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Lab. P=kT
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Topic: Lab. P=kT (Read 15519 times)
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sublime4510
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Lab. P=kT
«
on:
February 03, 2009, 05:37:44 PM »
The question is "In terms of ideal gas law, what variables are represented by k?" Isn't k just the amount P and T are proportional to one another? I have no idea how to answer this.
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Borek
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Re: Lab. P=kT
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Reply #1 on:
February 03, 2009, 05:41:30 PM »
Express k in terms of n, R and V.
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ChemBuddy
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sublime4510
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Re: Lab. P=kT
«
Reply #2 on:
February 03, 2009, 05:42:46 PM »
PV=nRT?
I don't understand what you mean, can you explain please?
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Borek
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Re: Lab. P=kT
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Reply #3 on:
February 03, 2009, 06:21:23 PM »
Let's say you have ax=by. You are told that x=ky and you are asked to find out what k is.
x = (b/a) y
x = k y
Compare these two - obviously k = b/a.
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ChemBuddy
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sublime4510
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Re: Lab. P=kT
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Reply #4 on:
February 03, 2009, 06:24:36 PM »
So would it be K=nR/V?
Also thanks for helping.
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Borek
Mr. pH
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Re: Lab. P=kT
«
Reply #5 on:
February 04, 2009, 03:25:18 AM »
That's it
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ChemBuddy
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Lab. P=kT