[kaylaalicia]

[Borek]

8.The equilibrium position is independent of the initial concentrations.

You mix 1 mole of H₂O with 1 mole of CO in one vessel and 2 moles of H₂O with 1 mole of CO in another vessel. Is equilibrium position identical?

Please show the reasoning behind answers to 5 & 6.

[kaylaalicia]

My reasonings for #5 and #6 are as follows:

5. I said true. Since all equilibrium reactions are dynamic, the carbon 14 will be distributed in all of the compounds that contain C
6. I said true to this one as well because enthalpy must be taken into consideration as a forward and reverse rxn might not have the same Kp.

[Borek]

I said true. Since all equilibrium reactions are dynamic, the carbon 14 will be distributed in all of the compounds that contain C

OK

I said true to this one as well because enthalpy must be taken into consideration as a forward and reverse rxn might not have the same Kp

Enthalpy doesn't matter in the termostated experiment. And while equilibrium constant may have different value depending on the way you write the reaction, it is a property of the system, not of the way it is described.