[mr cool]

[ARGOS++]

[mr cool]

[macman104]

First:[/b] don't i use half of 4.184 because, i start in ice?

No you don't.  Were you taught that, or did you read that somewhere? 

Also, I really do not recommend using an online conversion tool unless you can convert the units by hand first.  Almost all work in chemistry requires being able to convert units, or use dimensional analysis (which is what you can use to convert units).  If you are not comfortable with those techniques it is going to make your life only harder later on (even later in the semester).

[mr cool]

no im pretty good at dimensional analysis it's just that i was frustrated so i just took the easy way out

[ARGOS++]

[mr cool]

[ARGOS++]

Dear reezyfbaby;

Sorry, - Yes!

Please do it only stepwise!  Please start with First: .

Good Luck!
                    ARGOS⁺⁺

[mr cool]

Dear reezyfbaby;

Sorry, - Yes!

Please do it only stepwise!  Please start with First: .

Good Luck!
                    ARGOS⁺⁺

oh you want me to do #1 first ? oki...

85000 kj / 4.1845 = 20313


P.S. Here is another problem i was trying in the meantime...

What is the final temperature of a 50.00g sample of ice at -10.00*C if it is exposed to 59.75 J of energy and remains ice?

(.5 cal/g)(50.00g)(F- ^-10.00*C) = 250 cal
25 cal (F - ^-10*C) =250 cal
25 cal(F) + ^-250 cal = 250 cal
-225 cal = 250cal
250cal / -225 cal = 0.9 *C 

?

[ARGOS++]

[mr cool]

[ARGOS++]

[mr cool]

4563 left?

[ARGOS++]

[mr cool]