[ARGOS++]

Dear reezyfbaby;

Bravo!,  -  You did it!

Please think once again how we did it!

For your new Question:  You mixed Joules up with calories!

Good Luck!
                    ARGOS⁺⁺

[mr cool]

Dear reezyfbaby;

Bravo!,  -  You did it!

Please think once again how we did it!

For your new Question:  You mixed Joules up with calories!

Good Luck!
                    ARGOS⁺⁺

where did i mix them up? i don't see joules anywhere in that problem.

[ARGOS++]

Dear reezyfbaby;

Can you identify:  59.75 J in your question/problem? J stands for Joules!

Good Luck!
                    ARGOS⁺⁺

[mr cool]

Dear reezyfbaby;

Can you identify:  59.75 J in your question/problem? J stands for Joules!

Good Luck!
                    ARGOS⁺⁺

yea but i converted 59.75 joules into 250 calories. i know that J stands for Joules.

[ARGOS++]

Dear reezyfbaby;

Remember!:  For that you have to divide it, - not multiply!

Good Luck!
                    ARGOS⁺⁺

[mr cool]

Dear reezyfbaby;

Remember!:  For that you have to divide it, - not multiply!

Good Luck!
                    ARGOS⁺⁺

oh, that would explain it lol

so this is my first step?
(.5 cal/g)(50.00g)(F - -10.00*C) = 14.28 cal?

[ARGOS++]

[mr cool]

[ARGOS++]

[mr cool]

[ARGOS++]

[mr cool]

w/e i gave up on that problem because it frustrated me and i started the last one....

26.46 KJ of energy is released from 10.00 grams of steam as it condenses from 125.00*C.  What is the final temerature of the condensed water?

(.5 cal/g *C)(10.00g)(100-125) + (-540 cal/g)(10.00g)+(1.0 cal/g)(10.00g)(F-100*C) = 6323 calories

-125 cal + 5400 cal + 10 cal/g(F-100*C)=6323 calories

(10.00 cal/g)(F^o - 100*C) = 1038 calories

10.00 cal/g F^o

1038 calories
------------- =  103.8 *C
10.00 cal/g F^o

[ARGOS++]

[mr cool]