Given the following data:
S + 1.5O2 --> SO3 Delta H = -395.2 kJ
2SO2 + O2 --> 2SO3 Delta H = -198.2 kJ
Calculate Delta H for the reaction
S + O2 --> SO2
I can't seem to work this out. I wind up with S -> SO2, but there's no mol of O2 left behind on the reactants side.
I reversed the 2nd equation/reaction and cut it in half, so the SO2 would cancel. I left the other one the same. This allowed the 1.5 mol O2 to cancel, as well as the SO2.
What am I missing?