[Alquimista]

How would one draw lewis structures of compounds that have a positive or negative ions, like OH - or H3O+ for example? Here's my solution for OH- the oxygen atom has one electron leftover, so that's why there is a negative ion. .correct? Except I'm uncertain about the other compound since I don't where to place the remaining H atom

Btw, this isn't a homework question or anything to do with school. I'm just interested in chemsitry.

Looking forward.

[Alquimista]

14 views and not a single reply? It must be a sunday lol

[sjb]

It may be easier to split this into the H₂O and H⁺ structures, then consider the nature of the bond.

[Jhon Alison]

I do agree with sjb..try his suggestion..because i think you can't have such chemical formula like H₃0₊..that's for certain..
Of course, H₃0₊ does not exist separately like molecules, but H₃0₊, H₅O₂⁺ and H₇O₃⁺ were found in the crystal structures of strong acids hence chemists should be familiar with them.

[Borek]

I do agree with sjb..try his suggestion..because i think you can't have such chemical formula like H₃0₊..that's for certain..
Of course, H₃0₊ does not exist separately like molecules, but H₃0₊, H₅O₂⁺ and H₇O₃⁺ were found in the crystal structures of strong acids hence chemists should be familiar with them.

You first wrote that one can't have H₃O⁺, than you wrote that it was found in crystal structures. You contradict yourself.

[mahar.sean]

I may be being too simple, by Lewis structure I assume you mean Lewis Dot Structure.
Something helpful I was taught is that, let's say your dealing with Carbon a four valence electron element- place one dot at top, bottom, and each side.  For other elements use more or less dots.  The element to be bonded (Lewis dot style) use x es for its' valence.  Dots usually are used for symbol for electrons available for bonding...  I'm starting to trip over my words...I should just delete this, although there is a slim chance it may help, therefore I add it and see if a more experienced member can untangle my verbage.    I do know that this method is very helpful in determining if lone pairs are present.   

[LQ43]

See below

For resonance structures, vary the position of the double bonds