November 01, 2024, 12:24:12 AM
Forum Rules: Read This Before Posting


Topic: AP Chemistry:For the following rxn: CO2(g)+H2(g)<-->H2O(g)+CO(g), equilibrium is  (Read 7234 times)

0 Members and 1 Guest are viewing this topic.

Offline raiderhader2

  • New Member
  • **
  • Posts: 6
  • Mole Snacks: +0/-1
achieved at 2000K
Following equilibrium concentrations:
[H2]=0.20 M
[CO2]=0.30 M
[H2O]=[CO]=0.55M

When the system is cooled from 2000K to a lower temperature, 30.0% of the CO(g) is converted back to CO2(g). Calculate the Kc at this lower temperature.

Here's what I tried:
[CO]=0.55M-(0.55M)(0.3)=0.39M
[H2O]=0.39M
[CO2]=0.30M+90.55M)(0.3)=0.47M
[H2]=0.20M+(0.55M)(0.3M)

Kc=(0.39M)^2/[(O.47M)(0.37M)]=0.87

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27820
  • Mole Snacks: +1808/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
[H2O]=0.39M

Seems like you are on the right track, you just missed that water concentration must change as well.

ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Vidya

  • Full Member
  • ****
  • Posts: 839
  • Mole Snacks: +46/-62
  • Gender: Female
  • Online Chemistry and Organic Chemistry tutor
    • Online Chemistry Tutor
I think you have calculated right equilibrium concentrations.Your water concentration is also  right.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27820
  • Mole Snacks: +1808/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
I think you have calculated right equilibrium concentrations.Your water concentration is also  right.

Yep. I have misread the solution. My bad.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links