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Topic: calculate H+ of the following mixure.  (Read 13219 times)

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Offline Borek

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Re: calculate H+ of the following mixure.
« Reply #15 on: September 28, 2012, 06:11:18 PM »
Quote from: shanmac on September 28, 2012, 06:08:07 PM
9.5 x 10^-9 = x2 ÷ (6.25 x 10^-5 -x)

You are on the right track, but as AWK pointed earlier - this should be concentration, not number of moles.
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Offline shanmac

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Re: calculate H+ of the following mixure.
« Reply #16 on: September 28, 2012, 06:18:12 PM »
Oh so close!

Have I finally got it now...?

Ka nicotine= 10 -8.02 = 9.5 x 10^-9

9.5 x 10^-9 = x2 ÷ (8.33 x 10^-4- x)
x= 2.8 x 10^-6 = [H+]

(pH = 5.55)

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Offline Borek

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Re: calculate H+ of the following mixure.
« Reply #17 on: September 28, 2012, 06:21:20 PM »
That's what I got as well.
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Offline shanmac

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Re: calculate H+ of the following mixure.
« Reply #18 on: September 28, 2012, 06:26:06 PM »
Hooray!
Thanks for your assistance, I cannot tell you how helpful it has been to have someone guide me through the process.
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