December 24, 2024, 09:07:16 PM
Forum Rules: Read This Before Posting


Topic: Nitration of m-xylene through aromatic electrophilic substitution  (Read 8272 times)

0 Members and 2 Guests are viewing this topic.

Offline mreff555

  • Regular Member
  • ***
  • Posts: 29
  • Mole Snacks: +0/-0
Question

In the Nitration of m-xylene through aromatic electrophilic substitution, where would the NO2 most likely attach?

Here is my rationalization: Since both methyl groups are O/P directors it would be more likely to attach to carbons 2, 4 and 6. Additionally, Carbons 4, and 6 produce 2 sp2 stabilized resonance structures to carbon 2's 1 stabilized structure. So I would think 4 and 6 would be about equal with 2 being the runner up?
Did I miss anything?

Offline sjb

  • Global Moderator
  • Sr. Member
  • ***
  • Posts: 3653
  • Mole Snacks: +222/-42
  • Gender: Male
Re: Nitration of m-xylene through aromatic electrophilic substitution
« Reply #1 on: March 11, 2009, 11:18:02 AM »
I'd think that additions to 2 and 4 (and 6, but that's the same as 4, really) would give the same number of resonance hybrids, but electronics is not the only thing that can affect a reaction pathway....

Offline ufalynn88

  • Regular Member
  • ***
  • Posts: 24
  • Mole Snacks: +1/-0
Re: Nitration of m-xylene through aromatic electrophilic substitution
« Reply #2 on: April 17, 2009, 02:50:59 PM »
I think nitration at carbon 2 would not be favored due to sterics. to me 4 and 6 would be produced equally.

Offline aldoxime_amine

  • Full Member
  • ****
  • Posts: 191
  • Mole Snacks: +7/-4
Re: Nitration of m-xylene through aromatic electrophilic substitution
« Reply #3 on: April 17, 2009, 03:23:23 PM »
Wouldn't temperature make a difference,i.e, kinetic or thermodynamic competition..?

Sponsored Links