Hi, I was hoping someone could help me with this one question I can't seem to figure out:
Equal volumes of 0.12M AgNO3 and 0.14M ZnCl2 solution are mixed. Calculate the equilibrium concentrations of Ag+, Cl-, Zn2+, and NO3-
I started it off by calculating the moles of AgNO
3 to be .07 mol (.12M * .5L = .06) Assuming there was half a liter of each to make 1 liter of solution total.
I got moles of ZnCl
2 the same wayand got .07 moles.
Then I set up my reaction: Ag(NO
3) + ZnCl
2 AgCl
2 + Zn(NO
3)
I tried setting up an I.C.E. table to try to figure out the equilibrium concentrations but i can't seem to get any farther than that point. That is all the information i'm given about the problem and I don't know any kind of K
sp or anything.
Any Help will be appreciated,
Thanks,
Jim