December 23, 2024, 12:02:29 PM
Forum Rules: Read This Before Posting


Topic: acidifying to find partition coefficient  (Read 5470 times)

0 Members and 2 Guests are viewing this topic.

Offline gloinddark

  • Regular Member
  • ***
  • Posts: 23
  • Mole Snacks: +0/-0
  • Gender: Female
acidifying to find partition coefficient
« on: April 15, 2009, 10:31:40 AM »
during an experiment to find the partition coefficient of iodine in water and iso-octane, the mixture of iodine, iso-octane and water was acidified before allowing the phases to separate. i cannot understand the reason why it was acidified, any help will be appreciated.

Offline ARGOS++

  • Sr. Member
  • *****
  • Posts: 1489
  • Mole Snacks: +199/-56
  • Gender: Male
Re: acidifying to find partition coefficient
« Reply #1 on: April 15, 2009, 05:34:27 PM »
Dear gloinddark;

It could be to protect the building of "Triodide" what makes the I2 much more water-soluble and gives inadequate results for the coefficient.

You may read under "Characteristics" on:   http://en.wikipedia.org/wiki/Iodine#Characteristics 

Addition of strong acid will shift the equilibrium to the left of the following equation:
            http://en.wikipedia.org/wiki/Triiodide#Formation_and_structure 

I hope to have been of help to you.
Good Luck!
                    ARGOS++

Sponsored Links