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Topic: Dissociation Equations  (Read 5982 times)

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Offline book_luvr

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Dissociation Equations
« on: April 16, 2009, 06:32:14 PM »
Okay so I'm really lost...this is the dissociation problem for silver chloride:
so I have :

AgCl (s) ...what do i do next? How do i know the charges of the ag and cl?
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Offline Borek

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Re: Dissociation Equations
« Reply #1 on: April 16, 2009, 06:39:13 PM »
Cl in all chlorides has always the same charge.
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Offline Arkcon

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Re: Dissociation Equations
« Reply #2 on: April 16, 2009, 06:41:58 PM »
For Cl, it's position in the periodic table will do nicely.  For Ag, yeah, that is a little tougher, by itself.  But you've been given the compound it forms, so you know it's charge must balance the Cl.
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Offline book_luvr

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Re: Dissociation Equations
« Reply #3 on: April 16, 2009, 07:10:08 PM »
Huh...i still dont know how to get its charge?
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Offline ARGOS++

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Re: Dissociation Equations
« Reply #4 on: April 16, 2009, 07:42:30 PM »
Dear book_luvr;

In this case:  Maybe that Wiki can help you for this time:
                      http://en.wikipedia.org/wiki/Silver_chloride

Good Luck!
                    ARGOS++
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Offline UG

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Re: Dissociation Equations
« Reply #5 on: April 16, 2009, 08:26:22 PM »
Chloride is always -1 and since AgCl is neutral Ag must be....?
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