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Offline o0CY0o

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Question on distillation
« on: April 23, 2009, 10:43:42 AM »
There are two special type of distillation
1. Steam distillation
2. Vacuum distillation

However, i got 2 questions about them.
1st, for steam distillation. The boiling point of the substance is lowered by introducing the vapour of the volatile liquid into the vessal. Is it true to say that, the "steam" introduced is the gaseous state of the evaporating substance? because if other substance is added, the partial pressure will not be affected.

2nd, for Vacuum distillation, the boiling point is lowered by extracting vacuum and make the appied pressure lower. Such that the saturated vapour pressure can meet the applied pressure faster. However, when we extract the vacuum in the flask, the vapour pressure will be reduced at the same time. Can anybody explain it?

Offline ARGOS++

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Re: Question on distillation
« Reply #1 on: April 23, 2009, 06:17:10 PM »

Dear o0CY0o;

Compare your statements with:
     1.)      http://en.wikipedia.org/wiki/Steam_distillation#Principle.5B1.5D 
     2.)      http://en.wikipedia.org/wiki/Vacuum_distillation 

Good Luck!
                    ARGOS++

Offline o0CY0o

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Re: Question on distillation
« Reply #2 on: April 24, 2009, 02:00:55 PM »

Dear o0CY0o;

Compare your statements with:
     1.)      http://en.wikipedia.org/wiki/Steam_distillation#Principle.5B1.5D 
     2.)      http://en.wikipedia.org/wiki/Vacuum_distillation 

Good Luck!
                    ARGOS++

Sorry. I cannot get any help from your quote. Could you give me some more?
Anyway, thx for replying

Offline ARGOS++

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Re: Question on distillation
« Reply #3 on: April 24, 2009, 03:49:32 PM »

Dear o0CY0o;

I hoped you would realise during comparison that your statements are at least quite inadequate, if not already partially wrong.

Sorry! - but you are using terms which have nothing in common with steam distillation or vacuum distillation like:  "introduced",  "of evaporating substance", "extracting vacuum", "applied pressure lower/faster", "vapour pressure will be reduced", and so on.

What is very surprising: You never used the term temperature, which is very important for both kind of distillation

Maybe you can reword your statements with the help of the given links so we are then able to correct your statements if it should still be required.

Good Luck!
                    ARGOS++

Offline o0CY0o

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Re: Question on distillation
« Reply #4 on: April 26, 2009, 07:56:01 AM »

Dear o0CY0o;

I hoped you would realise during comparison that your statements are at least quite inadequate, if not already partially wrong.

Sorry! - but you are using terms which have nothing in common with steam distillation or vacuum distillation like:  "introduced",  "of evaporating substance", "extracting vacuum", "applied pressure lower/faster", "vapour pressure will be reduced", and so on.

What is very surprising: You never used the term temperature, which is very important for both kind of distillation

Maybe you can reword your statements with the help of the given links so we are then able to correct your statements if it should still be required.

Good Luck!
                    ARGOS++


Tempreture is the not the control factor. You see, we cannot adjust the tempreture of the distillation setup as it is dependent to the distillate. If we need to change the boiling point of distillate, the pressure is the changing factor in the two setup. When pressure changes the boiling point also changes. Therefore, i don't understand how you want me to introduce the term tempreture inside the statment.

Thanks :)

Offline ARGOS++

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Re: Question on distillation
« Reply #5 on: April 26, 2009, 08:26:05 AM »

Dear o0CY0o;

Sorry!,  -  I don’t agree with you about the temperature!

If not the temperature, and especially lowering of the temperature, for distillation would be important, then everybody could do a normal/simple distillation instead.

You may also think about what you wrote (only one example!):
Such that the saturated vapour pressure can meet the applied pressure faster. However, when we extract the vacuum in the flask, . 
        ---   But it is not fasterin real it's at lower temperature!!

And both techniques are used to do distillation at a lower temperature to protect your product as good as possible from decomposition.

Good Luck!
                    ARGOS++

Offline o0CY0o

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Re: Question on distillation
« Reply #6 on: April 27, 2009, 01:52:20 PM »

Dear o0CY0o;

Sorry!,  -  I don’t agree with you about the temperature!

If not the temperature, and especially lowering of the temperature, for distillation would be important, then everybody could do a normal/simple distillation instead.

You may also think about what you wrote (only one example!):
Such that the saturated vapour pressure can meet the applied pressure faster. However, when we extract the vacuum in the flask, . 
        ---   But it is not fasterin real it's at lower temperature!!

And both techniques are used to do distillation at a lower temperature to protect your product as good as possible from decomposition.

Good Luck!
                    ARGOS++


The concept i was taught was the boiling point (i.e., "tempreture" you've mentioned)  is the thing which we need to make it lower by reducing the applied pressure or increasing the vapour pressure to make the applied pressure equals to the vapour pressure.

I don't even understand what TEMPRETURE are you refering to. We don't do simple distillation, but vacuum distillation is to lower the boiling point.
Please make clear that which tempreture are you refering to.

Cheers

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