The first thing that came to my mind was to mix an excess of each solid into some HCl and then filter off the solutions. Since the Al ion is smaller and more highly charged than the Zn ion, its solution will be more acidic and hence have a lower pH, allowing me to distinguish between the two.
The acidity depends on the concentrations of Al(OH)3 and Zn(OH)2 and HCl
Yea i just realised that after i posted, i completely overlooked the fact that the concentrations would not be the same.
try adding an acid to both of them (maybe sulphuric or HCl)
Now perform the usual qualitative salt analysis tests on both....
When you say qualitative analysis, what type of tests are you talking about? I thought about precipitation tests, but i cant think of any case where one of the ions will precipitate and the other wont.
Another thought i had was to use the mistake i made in my original idea. If i measure out equal masses of each solid and then slowly add HCl until it is all dissolved, i should find that one of the solids will require approximately double the amount of HCl than the other, which will identify it as the Al(OH)3?