[ozzlomo]

If a sample of an ideal gas has it's volume doubled while its temperature remains constant, and the original pressure was 100 Torr, what is the new pressure in Torr?

Boyle's law states that the Pressure of a gas is inversely proportional to the Pressure of a gas at a constant temperature; V ~ 1/P

Thus, if the volume is doubled when the pressure is 100 Torr; V ~ 1/100 Torr

Then, when the volume is doubled, then the pressure in the previously stated Boyle's law doubles, and thus:

V ~ 1/200 Torr = 0.005 Torr, or, 2V ~ 1/100 Torr = V ~ (1/100 Torr) / 2 = 0.005 Torr.

Please correct me if I'm wrong.

[Schrödinger]

Boyle's law does state that the Pressure of a gas is inversely proportional to the Pressure of a gas at a constant temperature; V ~ 1/P at constant temp.

so, P1*V1 = P2*V2.

So, 100*V = P2*2V
=> P2 = 50 Torr



You said:
Thus, if the volume is doubled when the pressure is 100 Torr; V ~ 1/100 Torr
Then, when the volume is doubled, then the pressure in the previously stated Boyle's law doubles, and thus:
V ~ 1/200 Torr = 0.005 Torr, or, 2V ~ 1/100 Torr = V ~ (1/100 Torr) / 2 = 0.005 Torr.
Please correct me if I'm wrong.


This is wrong.
if V~1/P
then 2V~2/P
The 2/P fraction is not the pressure.
P/2 is the pressure.
 
 
 

[ozzlomo]

I understand what I did wrong. Thanks for the prompt response!

[Borek]

Please read forum rules.

Don't cross post.

Topic locked.