I've got 1,1 dibromo pentane. If I am to dehydrohalogenate it using alc. KOH, I expect the product to be Pent-1-yne but the book that I've got here says the product would be Pent-2-yne. Can someone please explain why? If possible, pls include the mechanism of the conversion (the one in which terminal alkyne converts to internal alkyne)