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Topic: Need help showing that 1 atm is equal to 14.7 psi using the density of Hg  (Read 6205 times)

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Offline rmhughes

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Need help showing that 1 atm is equal to 14.7 psi using the density of Hg
« on: August 28, 2009, 03:05:44 PM »
I need help showing that 1 atm is equal to 14.7 psi using the density of Hg. (13.6 g/cm3)
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Offline MrTeo

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Re: Need help showing that 1 atm is equal to 14.7 psi using the density of Hg
« Reply #1 on: August 28, 2009, 03:37:12 PM »
Think that the pressure of an atmosphere is equal to that of a mercury column 760mm high. What's the pressure of a column of fluid of given density $$ \delta /$$?
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Offline rmhughes

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Re: Need help showing that 1 atm is equal to 14.7 psi using the density of Hg
« Reply #2 on: August 29, 2009, 12:32:28 AM »
Could you give me a little bit more guidance?
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Offline MrTeo

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Re: Need help showing that 1 atm is equal to 14.7 psi using the density of Hg
« Reply #3 on: August 29, 2009, 01:00:38 AM »
Ok. 1atm is 760mmHg which means that the pressure of a column of Hg (independently from the base surface, remember Stevin's law) 760mm high is equal to 1atm. Now, assuming a generic surface S try to express pressure in the form of:



Youl'll get the result in SI units, as you have mercury's density in g/cm3, but you only need to convert after that.
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The way of the superior man may be compared to what takes place in traveling, when to go to a distance we must first traverse the space that is near, and in ascending a height, when we must begin from the lower ground. (Confucius)
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