I understand how to do displacement equations where the molecules reacting have 2 ions
e.g: K2CO3 + NaOH --> KOH + Na2CO3
Do group 1 carbonates react with alkalis? I haven't come across this before.
Please use the subscript button on the editor. It makes the formulae much more readable e.g. K2CO3 becomes K
2CO
3 with little effort.
However I do not know how to do displacement equations where one of the molecules reacting has 3 ions and the other one has 2
e.g: C6H8O7 + K2CO3 --> ??
OR where both molecules reacting have 3 ions
e.g: K2Cr2O7 + C6H8O7 --> ??
(I am not sure it equations 2 and 3 are valid but i hope you get the idea)
Please can someone explain to me how to do equations like 2 and 3
I do not recognise C6H8O7 (or C
6H
8O
7). Being comprised of just carbon, hydrogen and oxygen the compound is going to be
covalent not
ionic.
First you need to find out the molecular formula for this compound. For example: methylamine: CH
3NH
2 gives some information about the bonding between the atoms whereas CNH
5 is pretty hopeless. The more atoms you get the more useless a simple listing of atoms with a single subscript becomes.
You need a more informative formula than : C
6H
8O
7. For the number of carbons it has a relatively high number of oxygens which need to bond to the carbons as either alcohol or carboxyl groups. Perhaps it is some kind of sugar?
http://www.rpi.edu/dept/chem-eng/Biotech-Environ/FUNDAMNT/rings.htmHowever, your formula is a bit "short" on hydrogens. I just don't recognise it - so it is difficult to determine if it has functional groups that will react with K
2CO
3 .
Clive