Okay. First, I'd like to remind the readers that I've finished second-year analytical chemistry in University. And I have honestly worked at a simple acid-base titration problem (for a friend) for almost 5 hours
. And it's absolutely not making sense to me.
Here's the deal. We're titrating 0.100 L of 0.1 M diethylamine (given K
b = 0.0855 with 1 M HCl.
I sincerely believe the reaction equation is:
Et2NH + HCL <--> Et2NH2+ + Cl-
and that the diethylamine acts as a base via:
Et2NH + H2O <--> Et2NH2+ + OH-
I've determined with a simple calculation that the pH of the initial solution (No HCl added) is 12.77
In my frustration, I've also figured out, that if the diethylamine completely dissociated the water, then the pH would reach its upper limit (for a 0.1 M solution) of 13.
Nonetheless, I'm looking to use the Henderson-Hasselbach equation...
pH = pK
a + log ( [Base] / [BH+] ) according to MANY sources (internet and otherwise)
The pKa is for the conjugate acid, BH+ (in this case Et
2NH
2+), and so:
pKa = pKw / pKb = pKw / -log(Kb) = -log(10-14) / -log(0.0855) = 12.93
Now, if we add say, 1 mL of the HCl solution, we are 1/10 of the way to the equivalence point. So base:conjugate acid is 9:1 and so [Base]/[BH+] = 9/1 = 9
So pH = pK
a + log ([Base]/[BH+]) = 12.93 + log 9 = 12.93 + 0.95 = 13.88
which first of all, is an INCREASED pH, and second of all, violates the upper bound of pH on a solution of 0.1 M.
SOMETHING is wrong with this logic, and I'm almost embarrassed to ask. But I have to. Thanks for your help.