[miss.strw]

I'm not sure but I think the answer is only (e) am I correct?

   

Considering only the energy levels

n = 1       n = 2       n = 3       n = 4

of the H atom, which of the following statements are true?

a)   Only three emission lines are possible

b)   Photons with the highest energy are emitted in a transition
        from   level   n = 4 to level   n = 3

c)   Photons with the highest frequency are emitted in a transition
        from   level   n = 4 to level   n = 3

d)   The emission line having the longest wavelength corresponds to a transition
        from   level   n = 4 to level   n = 3

e)   The emission line having the shortest wavelength corresponds to a transition
        from   level   n = 2 to level   n = 1

[Schrödinger]

No.

Think of the energy gap between successive energy levels.

[miss.strw]

No.

Think of the energy gap between successive energy levels.

a)   Only three emission lines are possible

b)   Photons with the highest energy are emitted in a transition
        from   level   n = 4 to level   n = 3

c)   Photons with the highest frequency are emitted in a transition
        from   level   n = 4 to level   n = 3

d)   The emission line having the longest wavelength corresponds to a transition
        from   level   n = 4 to level   n = 3

e)   The emission line having the shortest wavelength corresponds to a transition
        from   level   n = 2 to level   n = 1

[Schrödinger]

you struck off the right answer.

clue1: energy gap between 2 consecutive levels decreases as we move away from the nucleus.

clue2:  $$ E = \dfrac{hc}{\lambda}/$$

[miss.strw]

you struck off the right answer.

clue1: energy gap between 2 consecutive levels decreases as we move away from the nucleus.

clue2: 

a)   Only three emission lines are possible

b)   Photons with the highest energy are emitted in a transition
        from   level   n = 4 to level   n = 3

c)   Photons with the highest frequency are emitted in a transition
        from   level   n = 4 to level   n = 3

d)   The emission line having the longest wavelength corresponds to a transition
        from   level   n = 4 to level   n = 3

e)   The emission line having the shortest wavelength corresponds to a transition
        from   level   n = 2 to level   n = 1

I hope that I am correct this time. Thank you (snack) Please tell me if this is correct?

[Schrödinger]

You have certainly struck off the wrong answers.
But there is only one option that fits the bill.

Try using the clues.

[miss.strw]

You have certainly struck off the wrong answers.
But there is only one option that fits the bill.

Try using the clues.

a)   Only three emission lines are possible

b)   Photons with the highest energy are emitted in a transition
        from   level   n = 4 to level   n = 3

c)   Photons with the highest frequency are emitted in a transition
        from   level   n = 4 to level   n = 3

d)   The emission line having the longest wavelength corresponds to a transition
        from   level   n = 4 to level   n = 3

e)   The emission line having the shortest wavelength corresponds to a transition
        from   level   n = 2 to level   n = 1

This is so hard. T__T

i know that a is out.
b is wrong since small gap = small energy
c b/c low enger = low fq

[Schrödinger]

about a,b,c, you were right

OK i'll help you.

Note clues 1 and 2.

They mean that the energy difference between n=4 and n=3 is the least among all the different possibilities among n=1,2,3,4.

So, 4 to 3 transition should correspond to the least energy.
Since energy and wavelength() are inversely related, lesser the energy, greater the .

So, option d) is correct.

hope this helps.

[miss.strw]

God, I feel so dumb,
The blue one is that I am positive

a)   Only three emission lines are possible

b)   Photons with the highest energy are emitted in a transition
        from   level   n = 4 to level   n = 3

c)   Photons with the highest frequency are emitted in a transition
        from   level   n = 4 to level   n = 3

d)   The emission line having the longest wavelength corresponds to a transition
        from   level   n = 4 to level   n = 3

e)   The emission line having the shortest wavelength corresponds to a transition
        from   level   n = 2 to level   n = 1

i tot low engery = low freq T__T i dont understand what I am doing wrong?

while i'm doing this i was looking @ http://answers.yahoo.com/question/index?qid=20090922093943AAnVS6X

[Schrödinger]

isn't that question different from yours?
Don't get confused with it. Try starting afresh.

low energy does mean low freq

[miss.strw]

isn't that question different from yours?
Don't get confused with it. Try starting afresh.

low energy does mean low freq

answer: bcde

[Schrödinger]

no. the answer is just d.

[miss.strw]

no. the answer is just d.

thank you so much T__T i hope i understand it .

[Schrödinger]

Please don't hesitate to ask if you have problems.

[LoveInQuanta]

Hey hey, miss.strw!

I'm no expert by anyone's metric, but this is how I like to think of wavelengths/energy:

The shorter the wavelength, the more harmful the energy generated by that particle is. Think of the electromagnetic spectrum headed *right*, or shorter in wavelength, from the visible wavelengths. We're often told to stay out of the sun to avoid harmful UV rays, X-ray guns can in science fiction kill you (and in reality, you have to wear that protective lead vest when getting x-rays), and gamma rays, which have the shortest wavelength, are darn near uncontainable by anything, their energy is so high. Technology to harness gamma rays is relatively very, very new.

In short, the SHORTER it is, the more of a punch it packs - the higher its energy.

Hope this helps in the future.