[-SERS-]

I added some tin(II) chloride with aqueous potassium manganate and it turned to a cloudy yellow-brown - what is the product?

SnCl₂ + KMnO₄

I also added the tin(II) chloride to potassium dichromate which turned orange

SnCl₂ + K₂Cr₂0₇  ?

[sjb]

I added some tin(II) chloride with aqueous potassium manganate and it turned to a cloudy yellow-brown - what is the product?

SnCl₂ + KMnO₄

Which? Just a friendly heads up, as KMnO₄ is not potassium manganate.

[whatamidoing]

I added some tin(II) chloride with aqueous potassium manganate and it turned to a cloudy yellow-brown - what is the product?

SnCl₂ + KMnO₄

Which? Just a friendly heads up, as KMnO₄ is not potassium manganate.

^It's Potassium Permanganate.

With that said, I'm pretty new to this chemistry business so I'm not sure if everything I say after this is totally correct. If someone could swoop down and help me out with my errors I think we could both benefit maybe.

Tin would react with the manganate to get Sn(MnO₄)₂ (Tin has a charge of 2+, need manganate to balance- hence the ₂)
Chlorine would get with Potassium and you'd be left with 2KCl (Chlorine has a charge of 1-, Potassium has a charge of 1+, 2 Chlorine needs 2 Potassium)

Balanced and fuzzy equation might look something like: SnCl₂ + 2KMnO₄ -> 2KCl + Sn(MnO₄)₂

y/n?

[Borek]

Tin would react with the manganate to get Sn(MnO₄)₂ (Tin has a charge of 2+, need manganate to balance- hence the ₂)
Chlorine would get with Potassium and you'd be left with 2KCl (Chlorine has a charge of 1-, Potassium has a charge of 1+, 2 Chlorine needs 2 Potassium)

Balanced and fuzzy equation might look something like: SnCl₂ + 2KMnO₄ -> 2KCl + Sn(MnO₄)₂

Have you ever thought about trying a career as a fantasy writer? You are so wrong it is even difficult to classify it as a science fiction 

These are going to be a redox processes.

[whatamidoing]

Tin would react with the manganate to get Sn(MnO₄)₂ (Tin has a charge of 2+, need manganate to balance- hence the ₂)
Chlorine would get with Potassium and you'd be left with 2KCl (Chlorine has a charge of 1-, Potassium has a charge of 1+, 2 Chlorine needs 2 Potassium)

Balanced and fuzzy equation might look something like: SnCl₂ + 2KMnO₄ -> 2KCl + Sn(MnO₄)₂

Have you ever thought about trying a career as a fantasy writer? You are so wrong it is even difficult to classify it as a science fiction 

These are going to be a redox processes.

lololol
Well, listen. This is how things go in my fantasy world.

[AWK]

Probably you used a lab solution of SnCl₂ which is additionally acidified with HCl.
Then reaction proceeds as follows:
SnCl₂ + KMnO₄ + HCl = MnCl₂ + SnCl₄ + KCl + Cl₂ + H2O (unbalanced - this redox reaction has many solutions depending on molar ratio of SnCl₂ to KMnO₄ assuming always an excess of HCl)

I also added the tin(II) chloride to potassium dichromate which turned orange

SnCl2 + K2Cr207

Dichromate itself is orange.

potassium manganate

potassium manganate(VII) will be correct

[-SERS-]

Thanks for the replies. I haven't done redox equations for about nearly 2 years so I'm a bit rusty and probably need to open my 7th form textbook and have a bit of a read. Anywho,

5Sn²⁺ 5Sn⁴⁺ + 10e^-
10e^- + 16H⁺ + 2MnO₄^- 2Mn²⁺ + 8H₂O

Adding:
16H⁺ + 5Sn²⁺ + 2MnO₄^- 2Mn²⁺ + 8H₂O + 5Sn⁴⁺


3Sn²⁺ Sn⁴⁺ + 6e^-
6e^- + 14H⁺ + Cr₂O₇^2- 2Cr³⁺ + 7H₂O

Adding:
14H⁺ + 3Sn²⁺ + Cr₂O₇^2- 3Sn⁴⁺ + 2Cr³⁺ + 7H₂O


Correct?

[Borek]

Yes and no.

Seems to me at first glance that these are correctly balanced redox reactions.

Whether they precisely describe what you have seen I don't know, but somehow I doubt. Your pH was probably too high, besides, as AWK stated, chlorides could be oxidized to chlorine.

No idea about the second experiment, but there is a strong observational hint that in the first one reaction has not proceeded that far, but stopped earlier, with Mn(IV).