January 10, 2025, 02:54:31 AM
Forum Rules: Read This Before Posting


Topic: Limiting Reagent Question (my own not a problem)  (Read 2654 times)

0 Members and 1 Guest are viewing this topic.

Offline s3a

  • Regular Member
  • ***
  • Posts: 63
  • Mole Snacks: +0/-0
Limiting Reagent Question (my own not a problem)
« on: September 30, 2009, 01:20:35 PM »
Let's say there is a chemical equation:

x + 2y ---> Cz

where the numbers (none means 1) are the coefficients and the small letters are the chemicals.

Let's just imagine a random amount of chemical x. Let's say that that random value is 0.5 mol and that there is 1 mol of chemical y. If the ratio was 1:1, I would know that the limiting reagent would be the chemical that there is less of which would be chemical x (again, if the ratio was 1:1). But lets say this is not the case.

Like my logic is: if you have twice as much of chemical y but you also need twice as much of it, then how do you know which is the limiting reagent?

Any help would be GREATLY appreciated!
Thanks in advance!

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27894
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Limiting Reagent Question (my own not a problem)
« Reply #1 on: September 30, 2009, 01:58:19 PM »
If they react 1:2 and you have twice as much of the second, neither is limiting - you just have stoichiometric amounts and they will be both used to the end.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links