Well I just started Chemistry again in college, but my memory isnt holding up too well after 2 years of doing nothing chemistry related. It is a fairly basic question which has me stumped. We use web assign so those of you who are familiar with it know how horrid and demotivating those red X's can be.
Anyway here is the question.
Upon strong heating, Cu2(CO3)(OH)2 or Cu3(CO3)2(OH)2 decomposes to leave CuO(s) in the heating crucible. Upon heating of 1.102 g of sample, 0.792 g remains. Calculate the %Cu in the sample.
Well what I am getting at is that you need %Cu/CuO X 1.102. Or %Cu/.792 X 1.102.
However that is wrong and I cannot find another way around it. Hopefully someone can point me in the right direction. I am not here for an answer as I am for the procedure.
Thanks guys!