A particular deposit of ore contains 32.6% Gold(I) Oxide (Let's ignore the patent instability of such a molecule). How many Kilos of Ore would have to be mined in order to collect 120 grams of gold?
I have established the formula as Au2O. I know there are going to be 2 moles of Gold per mole of Au2O. I know the molar mass of Au2O is 409.9326 g/mole, and the mass of the Gold within is 393.9331 g/mole. Finally, I know that 120 grams divided by 393.9331 g/mol means that it's .3046 moles.
I have ground to a halt here. I can't make the mental leap needed to finish the problem, if I knew what to find out next, I might be able to solve this, but right now I can't seem to do this myself.