January 11, 2025, 06:40:26 AM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Simple stoich problem. Can't finish it. :(  (Read 5275 times)

0 Members and 1 Guest are viewing this topic.

Offline nightowl1

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-0
Simple stoich problem. Can't finish it. :(
« on: October 12, 2009, 12:21:28 AM »
Given 10.0g of NaOH, what volume of a 0.100M solution of H2SO4 would be required to react all the NaOH?
Okay,
So I balanced the equation I just don't know what to do next.

2NaOH + H2SO4   --------->   Na2SO4 + 2H2O
Logged

Offline sjb

  • Global Moderator
  • Sr. Member
  • ***
  • Posts: 3653
  • Mole Snacks: +222/-42
  • Gender: Male
Re: Simple stoich problem. Can't finish it. :(
« Reply #1 on: October 12, 2009, 01:56:59 AM »
How many moles is 10.0g of NaOH?
Logged

Offline nightowl1

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-0
Re: Simple stoich problem. Can't finish it. :(
« Reply #2 on: October 12, 2009, 02:29:19 AM »
0.25 moles NaOH
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27894
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Simple stoich problem. Can't finish it. :(
« Reply #3 on: October 12, 2009, 03:32:46 AM »
OK, now, how many moles of H2SO4 will react with 0.25 moles of NaOH?
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline nightowl1

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-0
Re: Simple stoich problem. Can't finish it. :(
« Reply #4 on: October 12, 2009, 03:43:51 AM »
0.25?
I do not know :(
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27894
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Simple stoich problem. Can't finish it. :(
« Reply #5 on: October 12, 2009, 04:08:15 AM »
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline nightowl1

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-0
Re: Simple stoich problem. Can't finish it. :(
« Reply #6 on: October 12, 2009, 04:33:56 AM »
Where you pointing out the mole to mole ratio? 2 to 1 right?

0.25molesNaOH (1mole H2SO4  /  2 mole NaOH)   =  0.125mol H2SO4
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27894
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Simple stoich problem. Can't finish it. :(
« Reply #7 on: October 12, 2009, 05:04:32 AM »
OK, and the final touch - what volume of the 0.1M solution contains 0.125mol H2SO4?
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline nightowl1

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-0
Re: Simple stoich problem. Can't finish it. :(
« Reply #8 on: October 12, 2009, 05:17:59 AM »
So your asking to find the mass of H2SO4  ?

0.125mol H2SO4 [(98g H2SO4) / (1 mole H2SO4)]

= 12.25gH2SO4

Do i need to convert to ml, if so how?
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27894
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Simple stoich problem. Can't finish it. :(
« Reply #9 on: October 12, 2009, 05:27:55 AM »
No!

What is definition of molar concentration?
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline nightowl1

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-0
Re: Simple stoich problem. Can't finish it. :(
« Reply #10 on: October 12, 2009, 05:29:13 AM »
M= moles of solution / volume in Liters
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27894
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Simple stoich problem. Can't finish it. :(
« Reply #11 on: October 12, 2009, 05:34:31 AM »
OK, so you know you have 0.125mol of acid, and you know it has concentration 0.1M. Can you plug these values into the definition and solve for volume?
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline nightowl1

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-0
Re: Simple stoich problem. Can't finish it. :(
« Reply #12 on: October 12, 2009, 05:35:56 AM »
YES!!!! I get it now  ;D
Thank you
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links