Hi again
I would like you to "push" my solution as I am bit stuck there.
Problem:Standard solution is made and contains the following data:
0.5021 g ethyl propanoate
0.4927 g propyl ethanoate
4.7243 g acetone (solvent)
The standard solution and the sample are run twice each and the following results are obtained:
Component 1 Determ. 2 Determ.
Average of 2 determ. Area Area
Standard Ethyl propanoate 525 521 523
Propyl ethanoate 492 487 489.5
SampleEthyl propanoate 472 474 473
Propyl ethanoate 380 376 378
Use the external standard method to calculate the content of w/w% ethyl propanoate anw w/w% propyl ethanoate in the sample. Your calculations must be included.
My solution:1) At first I found average of two determinations
2) I can assume that the volume is 1 L
So C of the standards:
C(ethyl propanoate) = 502.1 mg/L
C(propyl ethanoate) = 492.7 mg/L
3) Calculation of C
sample in external standard method is:
C(x) = C(st) * (A(x) / A(st))
so I am calculating concentration of my sample:
C(ethyl propanoate) = 502.1 * (473 / 523) = 454.1 mg/L
C(propyl ethanoate) = 380.5 mg/L
4) w/w% ethyl propanoate anw w/w% propyl ethanoate in the sample.
And here I am stucked. Should I do something with solvent?
Thanks in advance!