A faster way to do it would be to note that the only two bonds you break are the C=C and H-Br and replace it with two C-Br, two C-H and a C-C bond. It saves a few seconds when you're in a rush, and the less keys you press the less likely you're going to make a mistake. You notice that the 4 C-H bonds you break then form back simply cancel each other out.
Of course, in real life, the C-H bond in ethene is different from the C-H bond in 1,2-dibromoethane but since your data doesn't provide for that difference, there's no need.