N = n * NA = 0.85 mol * 6.023 * 1023 = 5.12*1023 ions.
Close, but NaCl means TWO ions. No idea how the questions was worded.
The questions was "
How many ions (in total) are there in 50 g of NaCl?". I found how many moles 50 g of NaCl equals, and times that with Avogadro's number. Sounds good?
5CH3CH2OH + 4MnO4– + 12H+ → 5CH3COOH + 4Mn2+ + 11H2O
Since the ratio is 5:5 (or 1:1)
Assuming reaction is OK (no idea if oxidation ends here) ratio is not 5:5.
The reaction scheme was provided, so it's probably correct. However, am I considering the wrong reactant/product? It is Mn2
+ which causes the color to change, right? So from the coefficients, 5 moles of CH3CH2OH reacts with 4 moles of Mn2
+. Does this mean I have to use 5/4*n
permanganate added? So the concentration would be c= ((5/4)*4.692*10
-3 mol) / 25.00*10
-3 L?