[coles96]

the following data were collectedd during the titration of a solid sample of potassim acid phthalate ("KHP") with a solution of sodium hydroxide. THE NaOH solution was added to the KHP from a buret.

From the experimental data below, calculate the molarity of the NaOH solution

DATA

molar mass of potassium acid phtthalate= 204.g/mol
mass of weighing bottle plus KHP =23.6442g
mass of weighing bottle= 22.1793 g
initial buret reading= .10ml
final buret reading= 37.25ml


my attempt
khp+bottle-bottle=
23.6442-22.1793= 1.46G/204.2G/MOL=.00714mol this equeals the number of moles of Naoh used @ endpoi
buret reading difference is 37.15ml = .03715 l
so you take naoh used at end point and divide by that number
.007174mol/.03715L=.19311 mol/l of naoh

KINDA RIGHT?

[lancenti]

Heh, this looks a lot like a lab report I had to do very recently.

Please do put down an attempt, we definitely won't solve the problem for you but will point out where you went wrong to help you along.